Ÿþ > = > < 0 @ Q 2
ÿþR — ÿþ! 0 < > ; Q B K 03:25
ÿþM — ÿþ! 0 < > ; Q B (Ñòóäèÿ Ñåðãåÿ Òîïîëÿ) 03:59
ÿþ 0 ; 8 = 0 8 ? 8 = 0 — [ ÿþ = > 2 L 1 5 ; K 5 : > ; > : > ; L G 8 : 8 ( ; 0 4 8 < 8 @ ! > ; > 2 L Q 2 ) 03:39
ÿþ > = > < 0 @ Q 2 — ÿþ/ 03:50
ÿþA K 4 7 — / ÿþ > 2 A Q < 2 8 = > 2 0 B 0 2 > 4 : 0 02:37
+ ÿþ @ K A 8 > E > 4 O 3 8 M = 4 — ÿþ 5 @ 5 : > G Q 2 : 0 05:41
ÿþ" 0 B L O = 0 — ÿþ" 0 Q 6 = 0 O , 03:16